我想通过线程控制屏幕输入,但是我使用 InputStreamReader in = new InputStreamReader(System.in); BufferedReader buf = new BufferedReader(in); 的buf.readLine()方法,所以在调用该方法的方法中加抛出例外,那么我在使用线程时,重写RUN()方法,但是也同样对RUN()方法加抛出例外,这样做对吗?代码如下:
public class Group extends Thread {
Vector v = new Vector();
public void run() throws IOException
{
InputStreamReader in = new InputStreamReader(System.in);
BufferedReader buf = new BufferedReader(in);
do {
person tmp = new person();
v.addElement(tmp);
String AgeTemp;
System.out.print("Input name:");
tmp.setName(buf.readLine());
System.out.print("Input age:");
AgeTemp = buf.readLine();
tmp.setAge(Integer.parseInt(AgeTemp)) ;
System.out.print("Input sex:");
tmp.setSex(buf.readLine()) ;
System.out.print("Input univ:");
tmp.setUniv(buf.readLine()) ;
System.out.println("type 'q' to finish input.");
} while (!buf.readLine().equals("q"));
}
public static void main(String args[]) throws IOException{
Vector v=new Vector();
Group gp = new Group();
gp.start();
//gp.SortMothd();
//gp.StrPrint();
//gp.SortMothd(man);
}
}
