算法，

为什么我这样调用时

RandomStrg RSTR= new RandomStrg();

RSTR.setCharset("a-zA-Z0-9");

RSTR.generateRandomObject();　　《－－－－这一句

RSTR.getRandom();

RSTR.generateRandomObject();这一句，总在报

unreported exception java.lang.Exception; must be caught or declared to be thrown at line 90MM, column 10

public final void generateRandomObject() throws Exception {

// check to see if the object is a SecureRandom object

if (secure) {

try {

// get an instance of a SecureRandom object

if (provider != null)

// search for algorithm in package provider

random = SecureRandom.getInstance(algorithm, provider);

else

random = SecureRandom.getInstance(algorithm);

} catch (NoSuchAlgorithmException ne) {

throw new Exception(ne.getMessage());

} catch (NoSuchProviderException pe) {

throw new Exception(pe.getMessage());

}

} else

random = new Random();

}