java过滤器中如何转移地址?

例如:我要把/user/userName这个地址影射到
/user/userIndex.jsp?userId=userName

我是这样做的:


public void doFilter (ServletRequest request,
ServletResponse response,
FilterChain chain)
{

try
{
chain.doFilter (request, response);
String name = ((HttpServletRequest)request).getRequestURI();
String userName=name.substring(6);
request.getRequestDispatcher("/user/userLoad.jsp?userId="+userName).forward(request,response);

} catch (IOException io) {
System.out.println ("IOException raised in UserIndexFilter");
} catch (ServletException se) {
System.out.println ("ServletException raised in UserIndexFilter");
}
}


提示的错误是:
java.lang.IllegalStateException: Cannot forward after response has been committed
at org.apache.catalina.core.ApplicationDispatcher.doForward(ApplicationDispatcher.java:368)
at org.apache.catalina.core.ApplicationDispatcher.forward(ApplicationDispatcher.java:356)
at webLoad.UserIndexFilter.doFilter(UserIndexFilter.java:34)

请问老大到底要怎么做?

chain.doFilter (request, response);是转移到下一个filter
而你又想forward到一个jsp,到底你想往哪里走?

一般在filter中不会forward到jsp的。

不好意思,学艺不精!

谢谢老大